I meant E/M = 30/100.
Pm =133 W * 0.3 * 1.8 = 71.8 W but
Pr = 240 / 0.3 / 1.8 = 444 W
So, with the 30/100 SL assistance, the rider has to input as much as 444 W leg power to max the motor out.
Exactly, but E ≠ M in that case.
Let Px be the motor's peak power, and B the motor's boost. For the SL 1 and Creo 1, these are 240W and 1.8, resp.
Per Specialized documentation, above some saturation rider power Prs, Pm is capped at the motor saturation power Ps = Px (M / 100). Once the cap is in place, pedaling harder won't get you any more Pm than that.
In pseudocode,
if Pr <= Prs, Pm = Pr * B * (E / 100), else Pm = Px * (M / 100)
The blue graph of Pm vs. Pr above (Pr on x-axis) is a ramp of constant slope B E / 100 from Pr = 0 to Pr = Prs (orange vertical). At higher Pr, it's a flat (horizontal line) at Pm = Ps = Px (M / 100). The purple graph of total power at the crank (Pt = Pm + Pr) continues to rise after the orange vertical only because Pr does (red line).
It's useful to keep this geometry in mind. Since the ramp and flat have to meet at Pr = Prs, we must have
Prs B (E / 100) = Px (M / 100)
Solving for Prs gives
Prs = (Px / B) (M / E)
For the SL, Px / B = 133W. So when E = M on an SL,
Prs = 133W
Setting E = M couples the slope of the ramp to the height of the flat in such a way that they
always meet at the same Prs = 133W, independent of E or M. Play with the graph. You'll see.
This is what I was saying: 30/100 or similar E/100 modes reward hard pedalling. I recommend E/100 modes as the single assistance to take you from the start to the finish through all the hills en route (with optional OFF mode).
Agree. Using M = 100 delays saturation to higher effort, but E/100 with low E puts max motor power Px out of reach for many riders.
The ramp-and-flat geometry of Pm as a function of Pr is still there. For 30/100, the flat's just raised to Pm = Px = 240W, while the ramp lengthens to Pr = Prs = 133W (100 / 30) = 433W to meet it, just like you said.